4x^2+29x+52=0

Solution for 4x^2+29x+52=0 equation:

4x^2+29x+52=0

a = 4; b = 29; c = +52;
Δ = b2-4ac
Δ = 292-4·4·52
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-3}{2*4}=\frac{-32}{8}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+3}{2*4}=\frac{-26}{8}
=-3+1/4
$